How to return current_page in the lucky page?

[zw963]

I found i use current_page very frequently, only the current_page("some_path") is not enough,

is there a way to return current_page(a url on action)?

My current workaround is use current_path like following:

current_path = URI.parse(context.request.resource).path

I really consider current_page? is not so useful, because there are so many cases which need compare a something with current_page string.

Thanks

[jwoertink]

I'm not exactly clear on what you're looking to return, but would using context.request.path work better?

[zw963]

I'm not exactly clear on what you're looking to return, but would using context.request.path work better?

context.request.path works, but no document for this, maybe we can add a current_path method for this?

I found the code URI.parse(context.request.resource).path from the source of current_page? method, what is the difference of them?

[jwoertink]

what is the difference of them?

I honestly have no idea 😂 resource isn't documented, so I'm not really sure what it's purpose is